Question

In the figure, the equation of the straight line L is ...?
A. x-y-4=0
B. x-y+4=0
C. x+y-4=0
D. x+y+4=0

Answer 1

@ganeshie8

Answer 2

you have a point (4, 0) on the line

Answer 3

and you can find slope like this :
\[m = \tan (135)\]

Answer 4

use point slope form

Answer 5

oh the slope is tan135?!

Answer 6

no wonder why i cannot calculate it
i think that the slope is tan45

Answer 7

yes slope = \(\tan(\alpha)\)

\(\alpha\) is the angle between line and positive direction of x axis

Answer 8

oh i see

Answer 9

http://www.wolframalpha.com/input/?i=y-0%3Dtan%28135%29%28x-4%29

Answer 10

thank you so much