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find the derivative of f(x)=√x +1
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Try the power rule?
Wait, it is \(\Large f(x)=\sqrt{x+1}\) or \(\Large f(x)=\sqrt{x}+1\)?
the second one
d(x^n)/dx =n(x)^n-1
Yea, use the power rule, take it in this form: \(\Large f(x)=(x)^{1/2}+1\)
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then: \[f'(x)=\frac{ 1 }{ 2\sqrt{x} }\]
how come square root x stays at the bottom ?
The power turn negative.
You bring down the power, then subtract one.
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