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evaluate log equation help! 9^(logbase3(20))
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I don't know how to solve it in this format, could someone please tell me how these equations work?
\[\Large9^{\log_{3}(20)}=(3^2)^{\log_{3}(20)}=3^{2\log_{3}(20)}=\left(3^{\log_{3}(20)}\right)^2\]
what happens now that the 2 have been factored out?
@Zarkon
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