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prove: B-(B-A)=AintersectingB
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hmmmm I can demonstrate this using venn diagrams but I doubt that is sufficient
@dan815 How can we solve this with a mathematical approach?
Make a truth table
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\[B-A=B\cap A^{c}\]
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|dw:1416781448189:dw|
\[B-(B-A)=B-B\cap A^{c}=B\cap (B\cap A^{c})^c\]
ahhhh yeaaaaa I remember doing this stuff
\[B\cap (B\cap A^{c})^c=B\cap (B^c\cup A)=(B\cap B^c)\cup(B\cap A)\] \[=\emptyset\cup (B\cap A)=B\cap A\]
|dw:1416781481790:dw|
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