A cereal manufacturer has a tolerance of .75 ounce for a box of cereal that is supposed to weigh 20 ounces. Write and solve an absolute value inequality that describes the acceptable weights for "20 ounce" boxes. Please note: use '=' to write a greater-than-or-equal-to sign.

Question

A cereal manufacturer has a tolerance of .75 ounce for a box of cereal that is supposed to weigh 20 ounces. Write and solve an absolute value inequality that describes the acceptable weights for "20 ounce" boxes.


Please note: use '<=' to write a less-than-or-equal-to sign, and '>=' to write a greater-than-or-equal-to sign.

anonymous · Answer

@mathmath333

mathmath333 · Answer

it should be
$\Large20-0.75< 20+m<20+0.75$

mathmath333 · Answer

$\Large20-0.75\leq  20+m\leq 20+0.75$

mathmath333 · Answer

simplify it and use

$\Large -a\leq x \leq a\
\Large x=|a|$