Question

Find the real or imaginary solutions of each equation by factoring. 125x^3-27=0

Answer 1

okay i have it but its long k

Answer 2

First notice:
\[125x^3-27=(5x)^3-3^3\]
Difference of cubes:
\[a^3-b^3=(a-b)(a^2+ab+b^2)\]
Set \(a=5x\) and \(b=3\).