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cot ^-1(square root of 3)
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find a number whose tangent is \(\frac{1}{\sqrt3}\)
look on the unit circle to see where \[\sin(x)=\frac{1}{2},\cos(x)=\frac{\sqrt3}{2}\] that is the number you are looking for
yeah I know that but im doing the hw online and it keep saying that im wrong
did you put in \(\frac{\pi}{6}\)?
yes, i got it now. Thank you!
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yw
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