Question

Help pretty please:) Will give medal.
Slove:d+3/8d-2d+1/10d^2

A.)12d-4/40d^2
B.)12d^2-4/40d^2
C.)5d^2+7d-4/40d^2

Answer 1

\[\huge \frac{d+3}{\frac{8d-2d+1}{10d^2}}\]?

Answer 2

is there a typo there maybe? this seems unlikely

Answer 3

ooh maybe it is
\[\huge \frac{d+3}{8d}-\frac{2d+1}{10d^2}\] i get that is it

Answer 4

common denominator is \(40d^2\)

Answer 5

numerator is
\[4(d+3)-5d(2d+1)=-(10 d^2+d-12)\]

Answer 6

thank you