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Mathematics 17 Online
OpenStudy (anonymous):

2^x=32

OpenStudy (ageta):

x=5

OpenStudy (ageta):

Let's solve your equation step-by-step. 2x=32 Solve Exponent. 2x=32 log(2x)=log(32)(Take log of both sides) x*(log(2))=log(32)

OpenStudy (ageta):

\[\log \left(\begin{matrix}32 \\ 2\end{matrix}\right)\]

OpenStudy (jdoe0001):

hint: \(\bf 2^x=32\qquad {\color{brown}{ 2^5\to 32}}\quad thus\quad 2^x=2^5\)

OpenStudy (anonymous):

When you factor \(32\), you find out that: \(32 = 2^5\). So \[ 2^x = 2^5 \]

OpenStudy (ageta):

your welcome

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