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Solve for x: e^3x=10
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\(\large {\bf e^3x=10\implies log_{\color{brown}{ e}}({\color{brown}{ e}}^{3x})=log_{\color{brown}{ e}}10 \\ \quad \\ \textit{use the log cancellation rule of }log_{\color{brown}{ a}}{\color{brown}{ a}}^x=x }\)
\[ 10 = e^{\ln(10)} \]
take logs of each side 3x log(base e) e = log (base e) 10 3x = ln 10 x = ( ln 10) / 3
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