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Mathematics 9 Online
OpenStudy (anonymous):

Find the value of x and y.

OpenStudy (anonymous):

|dw:1416912941269:dw|

OpenStudy (anonymous):

the 3 is 3 sqrt2

OpenStudy (anonymous):

@calculusfunctions

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (michele_laino):

Please use the theorem of Pitagora to find the measure of y, and write your response. Please note that the triangle is isosceles right triangle

OpenStudy (anonymous):

idk how to do that

OpenStudy (michele_laino):

if you apply the theorem of pitagora, you will get: \[(3\sqrt{2})^{2}+(3\sqrt{2})^{2}=y ^{2}\] now write your result for y, please!

OpenStudy (anonymous):

ok just give me a min

OpenStudy (michele_laino):

don't worry, take your time!

OpenStudy (anonymous):

so y would equal 6 ?

OpenStudy (michele_laino):

that's right!

OpenStudy (anonymous):

ok thanks now time to solve for x

OpenStudy (michele_laino):

Ok!

OpenStudy (michele_laino):

plese note that: |dw:1416913843932:dw|

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