https://www.connexus.com/content/media/269102-4282011-123101-PM-1668238819/res00000/ppg/examview/images/es031-1.jpg (copy link to see picture) The two triangles above are similar. a. Find x using the ratio of the sides 14 cm and 16 cm: x/24 = 14 over 16. Show your work. b. Find x using the ratio of the sides 7 cm and 8 cm. Show your work. c. Explain why the answers to (a) and (b) should be the same. Please help, medal will be rewarded
This question is for Connexus students only? Alright.
Everyone can help me with this question, not just connexus students
When go to link, I get "Sorry! You must log in to view this content."
I'm sorry let me fix it
Here you go sorry for taking so long to upload it
Can you see the picture now?
Yeah we can.
Can you do part A?
I am having troubles with the whole thing, I am very sleep derived so it is hard to concentrate, and every time I try to do this question, the words get blurred and mixed up. But I have to complete this thing today, so I asked on here.
Sorry
Okay, so you were given \(\dfrac{x}{24}=\dfrac{14}{16}\). Do you know what to do to isolate x, right?
Um you have to make it equivalent to 14?
so the answer is 21/24?
No. Try multiply both sides by 24.
16x24=384 14x24=336
Oh I am so stupid! The question was supposed to be a. Find x using the ratio of the sides 12 cm and 16 cm: x/20 = 12 over 16. Show your work. b. Find x using the ratio of the sides 6 cm and 8 cm. Show your work. c. Explain why the answers to (a) and (b) should be the same. Please help, medal will be rewarded
I am sorry
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