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please help finding the value?
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Do you understand the notation they are using?
I understand there is a sequence an i=1 and I need to figure oyt what i3 is but I must be doing something wrong because Im not getting any of those ansers
do I add and then mutiply in the sequence?
\[\sum_{i-1}^{3}\] This means you have to put the value of i in \[4\times \frac{ 1 }{ 2 }^i-1\] one by one and add them
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till i=3
Then I would asume 7/2 but it can't be that simple right
ohh srry \[4\times (\frac{ 1 }{ 2 })^{(i-1)}\]
no the anser is 7
the expansion of this notation is \[4\times (\frac{1}{2})^{(1-1)}+4\times (\frac{1}{2})^{(1-2)}+4\times (\frac{1}{2})^{(1-3)}\]
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