Question

Find the horizontal or oblique asymptote of f(x) = -2x^2 + 3x + 6/x+1

y = -1
y = -2
y = 2x + 3
y = -2x + 5

Answer 1

that is (-2x^2+3x+6)/(x+1)?

Answer 2

if so the deg on top is one more than the deg on botton
you can find the oblique asymptote by dividing top by bottom

Answer 3

Thanks!