Question

Please check my work.

Answer 1

match the number and type of solutions for the following two functions in standard form.
f(x) = x^2 + 6x – 16
g(x) = x^2 +6x + 1

x^2 + 6x - 16 = 0
x^2 + 6x + 1 = 0
Match the following descriptions of the solutions to each of the functions above.
Two real irrationals solutions
x^2 + 6x + 1 = 0

x = -3 - 2 square root 2
x = 2 square root 2 - 3
Two real rationals solutions
x2 +6x - 16 = 0

(x - 2)(x + 8) = 0

Answer 2

looks fine i didnt go over it too hard but u look like u have the right idea