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If A+B+C=180 degrees, Sin(2A)+sin(2B)+sin(2C)=4sin(A)sin(B)sin(C)
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left hand side (LHS) = 2 sin A. cos A + 2 sin (B+C). cos (B - C)
=> 2 sin A. cos A + 2 sin (180 - A).cos ( B - C )
=> 2 sin A. cos A + 2 sin A. cos ( B - C )
=> 2 sin A [ cos A + cos ( B- C ) ]
( but cos A = cos { 180 - ( B + C ) } = - cos ( B + C )
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=> 2 sin A [ 2 sin B. sin C ] => 4. sin A. sin B. sin C
Do you know what identity formula this is using?
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