Ask
your own question, for FREE!
Mathematics
9 Online
OpenStudy (anonymous):
An earthworm of length 15cm is crawling along at 2cm/s. An ant overtakes the worm in 5seconds. How fast is the ant walking?
Still Need Help?
Join the QuestionCove community and study together with friends!
OpenStudy (anonymous):
2(cm/s)X5(seconds)=10cm (total length of the earthworm after walking for 5 seconds) 10cm+15(length of the worm)=25cm (total length that the ant needs to walk) 25cm/5s=5cm/s(the speed of the ant)
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Maci:
what are the best stock apps for people who want to start investing?
Twaylor:
genuienly how do i get better self control i keep watcing youtube and theres this
IzzyCookie:
|dw:1792074056138:dw| Uhm, I don't know where to ask this, but I'm in college welding at my community college, and I need help learning vertical welding for
thehearken:
not sure if this is considered spam, im sorry if it is, but does anyone have tips
Maci:
what are the best stock apps for people who want to start investing?
3 days ago
3 Replies
2 Medals
Twaylor:
genuienly how do i get better self control i keep watcing youtube and theres this
6 days ago
3 Replies
0 Medals
IzzyCookie:
|dw:1792074056138:dw| Uhm, I don't know where to ask this, but I'm in college welding at my community college, and I need help learning vertical welding for
1 day ago
9 Replies
1 Medal
thehearken:
not sure if this is considered spam, im sorry if it is, but does anyone have tips
1 week ago
2 Replies
1 Medal
