Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

. Help please with this. erinn's basic cell phone plan charge $54.99 for service plus $0.20 per minute beyond the included 500 minutes in the plan. how much will it cost erinn if she used her cell phone for 680 minutes in one month?

OpenStudy (anonymous):

so, you are going to start with the base service fee of 54.99. since it is an additional $.20 cents for each minute that goes over the initial 500, we can take away 500 from 680 because we know that the first 500 is free of charge. now we can start with the math. Since you took away the 500 from 680, you are left with 180 (The amount of minutes the exceeded his original data plan.) so we will need to multiply 180 times .20 (This will give us the total money needed to pay because he went over his original 500 minutes) then you will add the original base of 54.99 to the product of 180 and .20 which will give you the total money needed to pay the bill for that one month. 54.99+((680-500).20)= bill for the month (try to solve this equation to get your answer ;)

OpenStudy (anonymous):

i muilply 180 x 20 = 3600+54.99. So this will be the answer 3654.99?

OpenStudy (anonymous):

no, you need to multiply 180 by .20 you need the decimal to get the correct answer

OpenStudy (anonymous):

your answer should be in the double digits ;)

OpenStudy (anonymous):

36?

OpenStudy (anonymous):

no, not thirty six, its higher than that

OpenStudy (anonymous):

first, multiply 180 by .20 this should give you 36, then you need to add 54.99 to that

OpenStudy (anonymous):

ohh so 90.99?

OpenStudy (anonymous):

that should be it! :) good job

OpenStudy (anonymous):

thank you so much :)

OpenStudy (anonymous):

no problem, could you mark as best response, I would appreciate it :)

OpenStudy (anonymous):

thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!