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Write an equation in point-slop form of the line through joint J(4, 1) with slope -4. please help ?? :))
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y - y1 = m(x - x1) Where my is the slope and y1 and x1 are your points.
ooo, okay i get it now. haha, thank you so much !!
No problem. Remember The forms of: STANDARD Ax + Bx = C POINT-SLOPE y - y1 = m(x - x1) SLOPE INTERCEPT FORM Y = mx + b If you are EVER given something like a slope and points, and asked to graph it, first put it in POINT SLOPE FORM then solve for y, that will give you y = mx + b, and you can graph it then.
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