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Mathematics 16 Online
OpenStudy (anonymous):

hartnn help

OpenStudy (anonymous):

783 with a exponent of 9

hartnn (hartnn):

you mean \(9^x =783\) and you need to find 'x' ? does this question belong to logarithm topic ?

OpenStudy (anonymous):

yes

hartnn (hartnn):

783 with a exponent of 9 can also be written as \(783^9\) but thats highly unlikely \(for, ~~9^x = 783 \) Take logarithm on both sides

hartnn (hartnn):

and use the log property that \(\large \log a^b =b \log a\)

OpenStudy (anonymous):

ok I got it thanks

hartnn (hartnn):

\(then, ~~ \log 9^x = x \log 9\) and isolate x

hartnn (hartnn):

welcome ^_^

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