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783 with a exponent of 9
you mean \(9^x =783\) and you need to find 'x' ? does this question belong to logarithm topic ?
yes
783 with a exponent of 9 can also be written as \(783^9\) but thats highly unlikely \(for, ~~9^x = 783 \) Take logarithm on both sides
and use the log property that \(\large \log a^b =b \log a\)
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ok I got it thanks
\(then, ~~ \log 9^x = x \log 9\) and isolate x
welcome ^_^
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