Carlos is rappelling down a 478-foot cliff. He moves down the cliff at a rate of 8 feet per second. Which equation would represent the height Carlos is above the ground, H, after t seconds?
H = 478 - 8t
H = 478 + 8t
H = 8 + 478t
H = 8 - 478t

Question

Carlos is rappelling down a 478-foot cliff. He moves down the cliff at a rate of 8 feet per second. Which equation would represent the height Carlos is above the ground, H, after t seconds?
H = 478 - 8t
H = 478 + 8t
H = 8 + 478t
H = 8 - 478t

anonymous · Answer

the cliff is 478ft. He moves at 8ft/s down.(i.e. he will decrease)
therefore his height is after a certain amount of time , t, H= 478 - 8t