Question

find exact value, include radicals if there are any.
sin[tan^-1(-6)]

Answer 1

let arctan(-6)=u
then -6=tan(u)
make a right triangle in quadrant 4 since tan(u) is negative and arctan should only have outputs between -pi/2 and pi/2
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Answer 2

since tan^-1(-6) is -6 because tan^-1 is infinity to negative infinity

Answer 3

arctan(-6) isn't -6...