Question

An object is thrown from ground level at a velocity of 25.0 m/s at an angle of 20.0° above the horizontal. If there is a building 25.0 m away, at what height above the ground will the object hit the building?

Answer 1

Any help?

Answer 2

what are your thoughts on this problem?

Answer 3

I don't know where to start...

Answer 4

find the \[V{x}, V{y}\]

Answer 5

\[V{y}= V{o}\sin(\theta)\]

Answer 6

How will that help if I trying to figure out the height of the building?