A watering can dispenses water at the rate of 0.25 gallon per minute. The original volume of water in the can was 6 gallons. Which set of ordered pairs shows the volume of water in the can in gallons (y), as a function of time in minutes (x), from the first minute after the can starts dispensing water?
{(1, 6.0), (2, 5.75), (3, 5.50)}
{(6.0, 1), (5.75, 2), (5.50, 3)}
{(1, 5.75), (2, 5.50), (3, 5.25)}
{(5.75, 1), (5.50, 2), (5.25, 3)}
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OpenStudy (kitkat1):
Hey guys this question just poped out can u please help me
OpenStudy (anonymous):
i'll try
OpenStudy (kitkat1):
Ill give u another medal
OpenStudy (anonymous):
y=0.25x+6 is the function
OpenStudy (kitkat1):
Okay
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OpenStudy (kitkat1):
so plug in the numbers in this equation is there any shorter way?
OpenStudy (anonymous):
no there is no shorter way
OpenStudy (kitkat1):
Okay which numbers do I plug in?
OpenStudy (anonymous):
oh the coordinates
(x, y)
OpenStudy (kitkat1):
can u give me a example of one?
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OpenStudy (anonymous):
6.0=0.25*1+6
OpenStudy (kitkat1):
okay ill plug them all in
OpenStudy (kitkat1):
so for the 6.0 the answer looks like is 6.25
OpenStudy (anonymous):
yeah i'm cheking now is does look starnge
OpenStudy (kitkat1):
and the second one equals 6.25
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OpenStudy (anonymous):
i was wrong with the equation
the last one but i'm not sure
OpenStudy (anonymous):
x=0.25y+6
x-6=0.25y
OpenStudy (anonymous):
i was wrong with x and y
OpenStudy (anonymous):
tell me the result and medal if i'm correct
OpenStudy (kitkat1):
This will take me awhile
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OpenStudy (kitkat1):
Weird but I still get answers like 6.25
OpenStudy (kitkat1):
Nothing works out to an answer
OpenStudy (kitkat1):
I need to leave right now can u just give me the answer?
OpenStudy (anonymous):
the last one
OpenStudy (anonymous):
equations is x=0.25y+6
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OpenStudy (anonymous):
@Kitkat1
OpenStudy (kitkat1):
Okay so all the questions u answered were wrong
OpenStudy (kitkat1):
I just submited my quiz and all wrong
OpenStudy (anonymous):
ae you able to redo it
OpenStudy (anonymous):
sorry
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OpenStudy (kitkat1):
I will ask my teacher but all the questions will be different already