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Prime Factorization Exponents as Vector Components - Brainstorming!
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10 = 2^1*3^0*5^1 = (1,0,1) ?
|dw:1417153593194:dw| So here we have two separate axes which are two prime numbers p and q. And we have the vectors x and y. \[\bar x=p^sq^t = \langle s,t \rangle \\ \bar y = p^uq^v = \langle u, v \rangle\] and it makes a nice little box. I'm going to be a little slow, for some reason OS is lagging on me, but yeah you got it, the same ones wio and I have been playing with for the past several days. =P
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