A student set up a magnetic optical bench. The locations of the component holders for the crossed arrow target(CAT), and the lens(L), are as follows, respectively: 25.8 cm, 42.6cm. The offsets for CAT and the screen are 3.0mm, and the offset for L is 6.0mm. The image formed on the screen is twice the size of the object. (a) Calculate the position of the component holder of the screen. (b) Calculate the focal length of the lens. (c) Is the image inverted or upright? I know that m=-Si/So and Si=-2So and (1/f)=(1/o)+(1/i). I just do not know how in the blazes would you calculate Screen distance.

Question

A student set up a magnetic optical bench. The locations of the component holders for the crossed  arrow target(CAT), and the lens(L), are as follows, respectively: 25.8 cm, 42.6cm. The offsets for CAT and the screen are 3.0mm, and the offset for L is 6.0mm. The image formed on the screen is twice the size of the object. (a) Calculate the position of the component holder of the screen. (b) Calculate the focal length of the lens. (c) Is the image inverted or upright? I know that m=-Si/So and Si=-2So and (1/f)=(1/o)+(1/i). I just do not know how in the blazes would you calculate Screen distance.

anonymous · Answer

Here is a picture of the bench