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Which of the following is equal to square root of the cube root of 2? 2 to the power of 2/3 2 to the power of 3/2 2 to the power of 1/3 2 to the power of 1/6 @Jhannybean @TheSmartOne
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\[\sqrt[n]{x^m}= x^{m/n}\]
\[\sqrt[2]{\sqrt[3]{2}} = (\sqrt[3]{2})^{1/2}\] First sep.
step*
2and 3ver 2 is the answer rt
Then you take out the 1/3. \[\sf (2^{1/3})^{1/2} = 2^{1/2 \cdot 1/3}\] So what is \(\sf \frac{1}{2} \cdot \frac{1}{3}\)?
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1 over 5
@dmndlife24 you read the question wrong.
n0 6
2 x 3 \(\ne\) 5.
Good job :)
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