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OpenStudy (anonymous):
chapter 5:Indices and Logarithms simplify 16^x/2 + 4^x-1 @ganeshie8
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ganeshie8 (ganeshie8):
\[\large \rm 16^{\frac{x}{2}} + 4^{x-1}\] like this ?
OpenStudy (anonymous):
yup
ganeshie8 (ganeshie8):
I'll give a hint \[\large 16 = 4^2\]
OpenStudy (anonymous):
|dw:1417253335332:dw|
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