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Mathematics 6 Online
OpenStudy (anonymous):

chapter 5:Indices and Logarithms simplify 16^x/2 + 4^x-1 @ganeshie8

ganeshie8 (ganeshie8):

\[\large \rm 16^{\frac{x}{2}} + 4^{x-1}\] like this ?

OpenStudy (anonymous):

yup

ganeshie8 (ganeshie8):

I'll give a hint \[\large 16 = 4^2\]

OpenStudy (anonymous):

|dw:1417253335332:dw|

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