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Solve for x. -ax + 3b > 5 x > the quantity 3 times b minus 5 all over negative a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over negative a x < the quantity negative 3 times b plus 5 all over negative a
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@dan815
so we wanna get x by itself. what do we do first?
subtract b
yea so now we have -ax > 5 - 3b what now?
add a to the other side
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no. the -ax is multiplication and the opposite of multiplication is division. so we wanna divide both sides by -a. and once we do that, the the > flips and becomes < so x < (5 - 3b)/-a
oh ok
so the answer is d
thank you
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