Question

X^6-2X^4-X^2+2=0

Answer 1

What is the question? What is it asking you to solve?

Answer 2

solve by factoring

Answer 3

Solving by factoring, the answer would be: \[x = 1,i,-i,-1,\sqrt{2},-\sqrt{2}\]

Answer 4

how do you get those answers?

Answer 5

Do you know how?

Answer 6

The problem to solve is: \[x ^{6}-2x ^{4}-x ^{2}+2=0\]Multiply the exponent of x by 6-giving: \[x ^{6}\]Then you multiply the exponent of x by 4-giving: \[x ^{4}\]Multiply x4 and 2. Multiply x4 and 1. The x4 just gets copied along. The answer is x4. \[2\times x^{4} = 2x ^{4}\]\[x ^{6}-2\times x ^{4} = x ^{6}-2x ^{4}\]Multiply the exponent of x by 2-giving x2. The answer is x2. x2 evaluates to: \[x ^{2}\]The answer is: \[x ^{6}-2x ^{4}-x ^{2}\]The final answer is: \[x ^{6}-2x ^{4}-x ^{2}+2\]Which can also evaluate to: \[x = 1,o,-i,-1,\sqrt{2},-\sqrt{2}\]

Answer 7

Thanks lol i love you :)

Answer 8

Which can also evaluate to: \[x = 1,i,-i,-1,\sqrt{2},-\sqrt{2}\]

Answer 9

My Pleasure.

Answer 10

Do you have kik?

Answer 11

Private message me.

Answer 12

:(

Answer 13

Why the sad face?

Answer 14

Because i want your kik lol

Answer 15

I'll give it to you in PM.

Answer 16

Oh ok :)