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Calculus1 10 Online
OpenStudy (anonymous):

Show that if u = x2 + yz , then y2 x∂u + y∂u + z∂u = 0. ∂x ∂y ∂z

OpenStudy (perl):

looks like there might be a typo here then 'y2 ' x partial u

OpenStudy (perl):

or maybe I am misreading this

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