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OpenStudy (anonymous):
In quadrilateral ABCD, AE=x+2, and BE+3x-18. For what value of x is ABCD a rectangle?
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OpenStudy (anonymous):
OpenStudy (anonymous):
@felavin
OpenStudy (anonymous):
sorr for delay AE=X+2 BE=3X-18 THE diagonal of a rectagle are congruent ; so AC=BD AC=2AE=2*(X+2) BD=2BE=2*(3X-18)=6X-36 THEN WE HAVE: 2X+4=6X-36 ... SOLVE FOR X=? 40=4X ==> X=10
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