Question

Using a directrix of y = -2 and a focus of (2, 6), what quadratic function is created?

Answer 1

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Answer 2

looks like something i am learning but idk

Answer 3

and u get someone to help me please

Answer 4

ask @TheSmartOne

Answer 5

he knows everything

Answer 6

lol ikr

Answer 7

yes lol

Answer 8

can u try to help me please

Answer 9

@dumbcow

Answer 10

im bad at math. and idk why @thesmartone isnt coming hmm hold on let me tell him

Answer 11

oh hes viewing it wow

Answer 12

lol @TheSmartOne

Answer 13

can u help me please

Answer 14

i messaged him lol

Answer 15

oh kk

Answer 16

anything?

Answer 17

@SolomonZelman

Answer 18

try asking @Nnesha

Answer 19

@Nnesha can u help me

Answer 20

sorry im trying to get help as much as i can :p

Answer 21

I was afk

Answer 22

@jordanloveangel Also do not tag so many people as that is mass tagging and I don't want to see you get suspended.

Answer 23

yeah thats what you want us to think lol

Answer 24

sorry but can u help or nahh

Answer 25

What type of math is Just wondering...

Answer 26

algebra 1

Answer 27

@TheSmartOne The function would be (x-h)^2=4(a)(x-k)^2 is this the right answer

Answer 28

The standard form is (x - h)2 = 4a (y - k), where the focus is (h, k + a) and the directrix is y = k - a. If the parabola is rotated so that its vertex is (h,k) and its axis of symmetry is parallel to the x-axis, it has an equation of (y - k)2 = 4a (x - h), where the focus is (h + a, k) and the directrix is x = h - a.
Got it from : http://jwilson.coe.uga.edu/emt725/class/sarfaty/emt669/instructionalunit/parabolas/parabolas.html

Answer 29

thx

Answer 30

Is that all you need?

Answer 31

No problem. Sorry for the late reply...