As shown in the diagram, the height of building AB is 100 feet. The height of building CD is 50 feet. The buildings are on opposite sides of an avenue that is 90 feet wide. From a point E on the avenue, the measure of the angle of elevation to B is 55 degrees. Determine the distance from E to A to the nearest foot

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anonymous · Answer

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anonymous · Answer

Okay so if we consider the triangle EBA. Then we know that tan(55)=100/EA so EA=100/tan(55)=70.02 (70 feet).

anonymous · Answer

Thank you! I had the original setup I guess I got stuck