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having numbers 1-n which are randomly order what is the probablility that the numbers are in ascending or descending order? help thx
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damned unlikely i would imagine we can do it with 1,2,3 and see how it works only one arrangement is in ascending order out of a total of \(3!\) arrangements
since it is "ascending or descending" my guess is \[\frac{2}{n!}\]
since there is two ways it could happen right
am guess too that seems about right
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