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Algebra
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WILL FAN & MEDAL! How is the 3888 gotten in this problem? \[\sqrt[4]{3}*\sqrt[5]{2}\] = \[\sqrt[20]{3888}\]
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\[\huge \sqrt[4]{3} = \sqrt[4\times 5]{3^5} = \sqrt[20]{243} \]
\[\huge \sqrt[5]{3} = \sqrt[5\times 4]{2^4} = \sqrt[20]{16} \]
\[ \sqrt[20]{16\times 243} = \sqrt[20]{3888} \]
@Procrasturbator
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