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Use a finite sum to estimate the average value of f on the given interval by partition the interval into four subintervals of equal length evaluating f at the subinterval midpoints. f(x)=x^3 on [2,4]
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well the sum intervals have a width of 1/2 units so find f(2), f(5/2), f(3), f(7/2) and f(4) so rectangle 1 has a height (f(2) + f(5/2))/2 etc hope it makes sense
8+125/8+27+343/8+64=315/2
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