Question

Series

Answer 1

\[\sum_{n=2}^{\infty}\frac{ 1 }{ 1+(-1)^n+\ln(n)}\]
Find the nature of this series using comparison test

Answer 2

do u know what the comparison test is

Answer 3

kidding @dan815..?

Answer 4

to be safer, for all n >= 2 : \[\dfrac{1}{1+(-1)^n + \ln (n)}\gt \dfrac{1}{ 3+\ln (n)} \gt \dfrac{1}{\ln (100n)} \gt \dfrac{1/1000}{n} \]