Urgent *will medal*: The number of pizza meals sold by the concession stand was 3 times the number of hot dog meals. If the pizza meal cost $4, and the hot dog meal cost $2, and the total revenue from the meals was $658, how many of each meal were sold?

Thanks c:

Question

Urgent *will medal*: The number of pizza meals sold by the concession stand was 3 times the number of hot dog meals. If the pizza meal cost $4, and the hot dog meal cost $2, and the total revenue from the meals was $658, how many of each meal were sold?

Thanks c:

igreen · Answer

Hmm..I think they want you to make a system of equations.

2x + 4y = 658
x = 3y

Where x = pizza meals, and y = hot dog meals.

igreen · Answer

Sorry that's:

4x + 2y = 658
x = 3y

igreen · Answer

Graphing it will give us our solution. https://www.desmos.com/calculator/j4u3ujyk7h What is the solution? @ButterflyHope

igreen · Answer

The solution is the point where the two lines intersect.

igreen · Answer

Check:

Well, the solution is (141, 47)

That means there were 141 pizza meals and 47 hot dog meals.

Check:

Pizza meals are 3 times the number of hot dog meals.

Hot dog meals = 47

47 * 3 = 141.

Yep, it equals 141.

Pizza meals cost $4
Hot Dog meals cost $2

Total cost was 658.

4 * 141 = 564

2 * 47 = 94

564 + 94 = 658

Yep, it equals 658.

butterflyhope · Answer

Thanks :)