Question

What are the rules for solving for x?

8^x = (1/32)^(x-2)

Answer 1

\[8^x = (\frac{ 1 }{ 32 })^{x-2}\]

Answer 2

lol

Answer 3

@OdinMW, You might get better answers if you post this in the right section :) You are in the English section... Try posting it the Math section :)

Answer 4

Ohh man
you're right! :)

Answer 5

It's no problem friend :) Good luck friend!