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You are given the following graph of dP/dt. Use the figure above and the fact that P(0) = 30 to find the values below.
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i am going to guess that \(P(1)=29\) since the integral for that function from 0 to 1 is -1
yes you are correct
how would you go about doing the rest?
did you see how i got the -1?
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i know p(2) would be 28
not quite...
you got a square with base 1 height 1 area 1, but below the x axis so -1
ohhh okay
so how would you go about doing p(3)?
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|dw:1417558648417:dw|
\[P(0)=30\\ P(1)=30-1=29\\ P(2)=29-1=28\\ P93)=28-.5=27.5\]
so p(3) = (1/2)*bh which is 1/2(-1*1)
thats how you get the .5 and you just subtract it from the previous value?
yes
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got it!! thank you!!
yw
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