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Mathematics 13 Online
OpenStudy (anonymous):

You are given the following graph of dP/dt. Use the figure above and the fact that P(0) = 30 to find the values below.

OpenStudy (anonymous):

OpenStudy (anonymous):

i am going to guess that \(P(1)=29\) since the integral for that function from 0 to 1 is -1

OpenStudy (anonymous):

yes you are correct

OpenStudy (anonymous):

how would you go about doing the rest?

OpenStudy (anonymous):

did you see how i got the -1?

OpenStudy (anonymous):

i know p(2) would be 28

OpenStudy (anonymous):

not quite...

OpenStudy (anonymous):

you got a square with base 1 height 1 area 1, but below the x axis so -1

OpenStudy (anonymous):

ohhh okay

OpenStudy (anonymous):

so how would you go about doing p(3)?

OpenStudy (anonymous):

|dw:1417558648417:dw|

OpenStudy (anonymous):

\[P(0)=30\\ P(1)=30-1=29\\ P(2)=29-1=28\\ P93)=28-.5=27.5\]

OpenStudy (anonymous):

so p(3) = (1/2)*bh which is 1/2(-1*1)

OpenStudy (anonymous):

thats how you get the .5 and you just subtract it from the previous value?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

got it!! thank you!!

OpenStudy (anonymous):

yw

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