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Cot a - 2 Cot a / Cot a + 2 Cot a = Sin a / 3 Sin a
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also I assume this proving identities I think writing in terms of sin and cos might be a good start
It gets to -cos a/sin a * sin a / 3 cos a ! How to go about then
\[\frac{-\frac{\cos(a)}{\sin(a)}}{3 \frac{\cos(a)}{\sin(a)}} \]
write the division problem as a multiplication prob
\[\frac{-\cos(a)}{\sin(a)} \cdot \frac{\sin(a)}{3 \cos(a)}\]
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cancel some things
and also i assume the problem was \[\frac{\cot(a)-2\cot(a)}{\cot(a)+2\cot(a)}\]
If sin a cancels and also we cancel cos a/ 3cos a we will have only 1/3 ????....yes the problem is the correct one as you typed!!
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