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2x-7/x-5 >0 help please?
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what are you trying to find?
the two points I'm guessing the answer is\[(-\infty,\ -\frac{ 7 }{ 2 }) \cup (5,\infty)\]
Multiply the fraction by (x+5), each. You cross out the bottom part and end up with 2x-7(x+5). That's 2x^2-3x-35>0. Factor that.
That becomes (x-5)(2x+7).
thank u !
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