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lne^16x
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|dw:1417586366086:dw|
is the answer 16x
yes :)
\(\ln a^b = b \ln a\)
cool
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And : \[\log_a(a) = 1\]
ln means log to the base e.. \[\ln = \log_e\]
So: \[\ln_e(e) = 1\]
so the problem equals itself?
What?
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\[\log_e(e)^{16x} \implies 16x \cdot \log_e(e) \implies 16x \cdot 1 \implies 16x\]
oh ok thanks
:)
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