Question

3 cos(theta-60)=2 cos theta

Answer 1

What to do in this?

Answer 2

solve plzzzzz

Answer 3

hint:\[\cos(a-b) = \cos(a)\cos(b)+\sin(a)\sin(b)\]

Answer 4

\[3[cos(\theta -60)]=2\cos(\theta)\]\[3[\cos(\theta)\cos(60) + \sin(\theta)\sin(60)]=2\cos(\theta)\]

Answer 5

Started it off for you, go ahead and finish it.

Answer 6

got it... thaaaaaank you

Answer 7

No problem :)