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OpenStudy (anonymous):
Complete the equation for the linear function whose graph contains the points (-1,-2) and (3,10).
y+blank=blank(x+1)
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OpenStudy (anonymous):
@paki @iGreen @itsbribro
OpenStudy (anonymous):
Hiya :)
OpenStudy (itsbribro):
heyy (:
OpenStudy (anonymous):
Ok so usually I don't do this but, I just don't get this question. My bloody teachers are useless.
OpenStudy (itsbribro):
lol its okay but i just logged in awhile ago and im still kinda sleepy lol so maybe i can tag someone
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OpenStudy (anonymous):
Yea thats Cool :)
OpenStudy (itsbribro):
@LunyMoony @HaleyJlynn @helpmath123
OpenStudy (anonymous):
Hiyas :)
OpenStudy (anonymous):
um y aim kinda terrible at this kind of math lol
OpenStudy (anonymous):
LOL
Thats kool :)
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OpenStudy (lunymoony):
writing my graph
OpenStudy (anonymous):
Ok I just made my grpah
OpenStudy (lunymoony):
probably better than mine, lets see it
OpenStudy (anonymous):
Ok so technically I didn't make one . I printed one .
OpenStudy (lunymoony):
(-1,-2) and (3,10).
y+blank=blank(x+1)
=
-1y -2 = 3x +10
this seem right @itsbribro
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OpenStudy (lunymoony):
If so then its ....
-1y = 3x +8
-3x - 1y = +8
-3x = 8 + (1)y
3x = -8 -y
x= -8 -y/3
OpenStudy (anonymous):
Thanks Sooooooooo Much :) I am virtual giving you thousands of hugs :)
OpenStudy (lunymoony):
lol, np!
OpenStudy (anonymous):
If you ever need help In ELA or SS just ask me . I am fabulous at both.
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