Question

How is x/(3^n) + y/(3^n) = z/(3^{n-1}) in the following equation?

\[ a_{n}=\frac{6}{3^n}+\frac{9n}{3^n}=\frac{2+3n}{3^{n-1}} \]

Answer 1

\[ a_{n}=\frac{6}{3^n}+\frac{9n}{3^n}=\frac{2+3n}{3^{n-1}} \]

Answer 2

\[
\begin{array}~
\dfrac{6}{3^n}+\dfrac{9n}{3^n} &= \dfrac{6+9n}{3^n}\\~\\&=\dfrac{3(2+3n)}{3^n}
\\~\\ &=~~~~~~ \cdots
\end{array}
\]

Answer 3

Is that clear? @calyne

Answer 4

oh yes thanks nvm