Question

a probala has a vertex at (-1,0) and opens down what is the equation

Answer 1

\(\large \begin{array}{llll}


y=(x-{\color{brown}{ h}})^2+{\color{blue}{ k}}\\
x=(y-{\color{blue}{ k}})^2+{\color{brown}{ h}}
\end{array}
\qquad
\begin{array}{llll}
vertex\ ({\color{brown}{ h}},{\color{blue}{ k}})\\



\end{array}\)


bear in mind that, when a parabola opens downwards, it has a leading term with a negative coefficient