Mathematics
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OpenStudy (anonymous):
What is the perpindicular line of (-5,2) y=1/2x-3
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OpenStudy (anonymous):
-2x-1
OpenStudy (anonymous):
To find a perpendicular line to an equation, inverse the slope of the equation.
So, y=2x-3
OpenStudy (anonymous):
How did you figure that?
OpenStudy (anonymous):
the recipricol of 1/2 is -2
OpenStudy (anonymous):
so now you have
2=-2(5)+b
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OpenStudy (anonymous):
and solve for b
OpenStudy (anonymous):
nvm its actually
y=-2x-8
OpenStudy (anonymous):
sorry
OpenStudy (anonymous):
im having troubles
OpenStudy (anonymous):
2=-2(-5)+b
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OpenStudy (anonymous):
typo
OpenStudy (anonymous):
how did you get -2 from 1/2
OpenStudy (anonymous):
shouldn't it be a postive 2 not a negative
OpenStudy (anonymous):
(2,6), y=-1/4x+3
OpenStudy (anonymous):
its is opposite reciporical
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OpenStudy (anonymous):
not just opposite
OpenStudy (anonymous):
1/2 becomes 2/1 and then becomes negative
OpenStudy (anonymous):
so would i just do : 6=2/1(2)+b
OpenStudy (anonymous):
Then i would have 6=4+b
then -4 on both sides and 6-4=2 so b =2????
OpenStudy (anonymous):
or did i do that totally wrong...
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OpenStudy (anonymous):
uh oh i lost what i was typing
OpenStudy (anonymous):
a perpendicular slope to 1/2 is -2
OpenStudy (anonymous):
y=-2x+b
OpenStudy (anonymous):
then u plug in the coordinates from above
OpenStudy (anonymous):
and solve for b
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OpenStudy (anonymous):
ok so then would i have 6=-2(2)+b
OpenStudy (anonymous):
2=-2(-5)+b
2=10+b
-8=b
OpenStudy (anonymous):
ok thanks for the help i think i get this now
OpenStudy (anonymous):
then you remove the x and y coordinates and you have
y=-2x-8