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Mathematics 8 Online
OpenStudy (anonymous):

I need help in probabilities There are 36 jolly hobbits, 15 grumpy hobbits, 11 jolly leprechauns and 12 grumpy leprechauns. Find the probability that person randomly selected is jolly or a leprechaun

OpenStudy (sleepyjess):

What do you think you will do first?

OpenStudy (sleepyjess):

@Aethelswith Please do not give out direct answers.

OpenStudy (anonymous):

since it says that is jolly or a leprechaun i have 36 jolly hobbits, 11 jolly leprechauns and 12 grumpy leprechauns and i don't how to work the formula with 3 events @sleepyjess

OpenStudy (sleepyjess):

First you need to add up all of the hobbits and leprechauns.

OpenStudy (anonymous):

74 that wil be the total and wait if I'm right then i need the total of the jolly and leprechauns that will be 59 so it will be 59/74 = 0.747? (the answer need to be in decimals) @sleepyjess

OpenStudy (sleepyjess):

Find the probability that person randomly selected is jolly or a leprechaun = jolly+leprechaun/total

OpenStudy (anonymous):

it's 59/74 = 0.747 cause i have 36 jolly hobbits, 11 jolly leprechauns and 12 grumpy leprechauns @sleepyjess

OpenStudy (sleepyjess):

Ok, so you need it in decimal form? Or percent?

OpenStudy (anonymous):

decimal so that will be the answer can you help with another one if two household are independently selected, what is the probability that both have income in the $30,000- $39,999 range? Income 0- $9,999 6% $10,000-$19,999 9% $20,000- 29,999 13% $30,000-$39,999 28% $40,000-$49,999 18% $50,000-$59,999 17% $60,000 or more 9% when they give the chart i get confuse @sleepyjess

OpenStudy (sleepyjess):

Hmmmm... I'm not sure how to do this one but let me see if I can find anything.

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